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# Python Program to Check whether the Number is Armstrong Number or Not

###### Tutorialsrack 22/04/2020 Python

In the Python program, we will learn how to check whether the number is Armstrong number or not.

## What is an Armstrong number?

An Armstrong number is a number that is the sum of its own digits each raised to the power of the number of digits.

For Example,  153 is an Armstrong number.

(1)3 + (5)3 + (3)3= 153.

Here is the code of the program to check if the given number is Armstrong Number or Not.

### Program 1: Check 3 Digit Number is Armstrong or Not

##### Program 1: Check 3 Digit Number is Armstrong or Not
``````# Python Program to Check whether the Number is Armstrong Number or Not

# Take input from the user
num = int(input("Enter a number: "))

# initialize sum
sum = 0

# find the sum of the cube of each digit
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** 3
temp //= 10

# display the result
if num == sum:
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")
``````
##### Output

Enter a number: 5

5 is not an Armstrong number

Enter a number: 153

153 is an Armstrong number

### Program 2: Check nth Digit Number is Armstrong or Not

##### Program 2: Check nth Digit Number is Armstrong or Not
``````# Python Program to Check whether the Number is Armstrong Number or Not
# Take input from the user
num = int(input("Enter a number: "))

# Changed num variable to string,
# and calculated the length (number of digits)
order = len(str(num))

# initialize sum
sum = 0

# find the sum of the cube of each digit
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** order
temp //= 10

# display the result
if num == sum:
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")
``````
##### Output

Enter a number: 153

153 is an Armstrong number

Enter a number: 1634

1634 is an Armstrong number